sparsistency
Let mathbf b be a vector and define the support operatorname supp=i: mathbf bᵢ≠0 where…Let mathbf b be a vector and define the support operatorname supp( mathbf b)=i: mathbf bᵢ≠0 where mathbf bᵢ is the ith element of mathbf b. Let ̂mathbf b be an estimator for mathbf b. Then sparsistency is the property that the support of the estimator converges to the true support as the number of samples grows to infinity.
Значение
значений: 1(неисчисляемое)Let mathbf b be a vector and define the support operatorname supp( mathbf b)=i: mathbf bᵢ≠0 where mathbf bᵢ is the ith element of mathbf b. Let ̂mathbf b be an estimator for mathbf b. Then sparsistency is the property that the support of the estimator converges to the true support as the number of samples grows to infinity.
Происхождение
Blend of sparse + consistency.Blend of sparse + consistency.
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Однокоренные
связанных слов: 1Уроки к слову
уроков: 1- A1Исчисляемые и неисчисляемые существительные — Потому что оно может быть неисчисляемым